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0.9x^2+17x+25=0
a = 0.9; b = 17; c = +25;
Δ = b2-4ac
Δ = 172-4·0.9·25
Δ = 199
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{199}}{2*0.9}=\frac{-17-\sqrt{199}}{1.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{199}}{2*0.9}=\frac{-17+\sqrt{199}}{1.8} $
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